The atom having the valence-shell configuration $4 s^{2} 4 p^{5}$ $4s^2 4p^5$ would be in what group and period?

Question

31791 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-04T20:36:19

The atom would be in Period 4 and Group 17.

The valence shell configuration is ${4s}^{2} {4p}^{5}$ $"4s"^2 "4p"^5$ .

The principal quantum number (4) gives you the Period number.

Start with H in Period 1 and count down to the fourth row (Period 4).

That brings you to $K$ $"K"$ .

Location
(Adapted from Chemistry - About.com)

Now, start counting to the right through the $s$ $"s"$ -block to $Ca$ $"Ca"$ ( ${4s}^{2}$ $"4s"^2$ ) and the $d$ $"d"$ -block to $Zn$ $"Zn"$ .

Now that you have come to the $p$ $"p"$ -block, count five more atoms, for a ${4p}^{5}$ $"4p"^5$ configuration.

This brings you to the desired atom, $Br$ $"Br"$ .

You have counted horizontally through 17 atoms, so $Br$ $"Br"$ is in Group 17.

The atom having the valence-shell configuration 4s^2 4p^54s24p54s^2 4p^5 would be in what group and period?