The area of the rectangle is $(4x-3)$ long, by $(2x+5)$ wide, how do you find the area of the rectangle?

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Answer 1 · 2018-03-06T18:44:17

$A =8x^2 -14x -15$

You cannot find a numerical value for the area, but you can find an algebraic expression to represent the area.

In a rectangle: $A = l xxb$

$A = (4x-3)(2x+5)$

$= 8x^2+20x-6x-15$

$=8x^2 -14x -15$

If at a later stage, extra information is given about the value of $x$ , the actual area could be determined.

The area of the rectangle is (4x-3)(4x-3) long, by (2x+5)(2x+5) wide, how do you find the area of the rectangle?