Suppose #sin(x) = 9/11# and that #90 < x < 180, how do you find cos(x) and tan (x)? Trigonometry Right Triangles Relating Trigonometric Functions 1 Answer Nghi N. May 24, 2015 #sin x = 9/11 = 0.82# #cos^2 x = 1 - sin^2 x = 1 - 0.67 = 0.33 -> cos x = -0.57# (90 < x < 180) #tan x = 0.82/-0.57 = -1.44# Answer link Related questions What does it mean to find the sign of a trigonometric function and how do you find it? What are the reciprocal identities of trigonometric functions? What are the quotient identities for a trigonometric functions? What are the cofunction identities and reflection properties for trigonometric functions? What is the pythagorean identity? If #sec theta = 4#, how do you use the reciprocal identity to find #cos theta#? How do you find the domain and range of sine, cosine, and tangent? What quadrant does #cot 325^@# lie in and what is the sign? How do you use use quotient identities to explain why the tangent and cotangent function have... How do you show that #1+tan^2 theta = sec ^2 theta#? See all questions in Relating Trigonometric Functions Impact of this question 5099 views around the world You can reuse this answer Creative Commons License