State the x and y intercept: y = -8/9x -16 ?

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Answer 1 · 2018-04-13T03:46:23

#y#-intercept #= -16#
#x#-intercept #= -18#

Compare the equation to

#y= mx +c#

Where

Hence,

#c= -16#

i.e the #y#-intercept is #-16#.

At the #x#-intercept, #y=0#. Therefore, let #y=0#.

#y= -8/9x -16#

#0= -8/9x -16#

#8/9x= -16#

Divide both sides of the 'equal to' sign by #8/9#

#x= -18#

Hence, the #x#-intercept is #-18#.