State the x and y intercept: y = -8/9x -16 ?

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Answer 1 · 2018-04-13T03:46:23

$y$ -intercept $= -16$
$x$ -intercept $= -18$

Compare the equation to

$y= mx +c$

Where

Hence,

$c= -16$

i.e the $y$ -intercept is $-16$ .

At the $x$ -intercept, $y=0$ . Therefore, let $y=0$ .

$y= -8/9x -16$

$0= -8/9x -16$

$8/9x= -16$

Divide both sides of the 'equal to' sign by $8/9$

$x= -18$

Hence, the $x$ -intercept is $-18$ .