Solve for R: $T = \frac{1}{3} R - 15$ $T = 1/3R - 15$ ?

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Solve for R: $T = \frac{1}{3} R - 15$ $T = 1/3R - 15$ ?

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Answer 1 · 2017-09-03T18:22:38

See a process below:

Explanation:

Step 1) Add $15$ $color(red)(15)$ to each side of the equation to isolate the $R$ $R$ term while keeping the equation balanced:

$T + 15 = \frac{1}{3} R - 15 + 15$ $T + color(red)(15) = 1/3R - 15 + color(red)(15)$

$T + 15 = \frac{1}{3} R - 0$ $T + 15 = 1/3R - 0$

$T + 15 = \frac{1}{3} R$ $T + 15 = 1/3R$

Step 2) Multiply each side by $3$ $color(red)(3)$ to solve for $R$ $R$ while keeping the equation balanced:

$3 (T + 15) = 3 \times \frac{1}{3} R$ $color(red)(3)(T + 15) = color(red)(3) xx 1/3R$

$3 T + (3 \times 15) = \frac{3}{3} R$ $color(red)(3)T + (color(red)(3) xx 15) = color(red)(3)/3R$

$3 T + 45 = 1 R$ $3T + 45 = 1R$

$3 T + 45 = R$ $3T + 45 = R$

$R = 3 T + 45$ $R = 3T + 45$

Answer 2 · 2017-09-03T18:34:24

$R = 3 (T + 15)$ $R = 3(T+15)$

Or

$R = 3 T + 45$ $R =3T+45$

Explanation:

You need to make $R$ $R$ the subject of the formula.

$\frac{1}{3} R - 15 = T \leftarrow$ $color(blue)(1/3R)-15 = T" "larr$ isolate the term which contains $R$ $R$

Add $15$ $15$ to both sides to get:

$\frac{1}{3} R = T + 15 \leftarrow$ $1/3color(red)(R)= T+15" "larr$ isolate $R$ $R$ by multiplying by $3$ $3$

$R = 3 (T + 15)$ $R = 3(T+15)$

This can also be simplified to

$R = 3 T + 45$ $R =3T+45$

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2 Answers

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