Solve for R: #T = 1/3R - 15#?

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Answer 1 · 2017-09-03T18:22:38

See a process below:

Step 1) Add #color(red)(15)# to each side of the equation to isolate the #R# term while keeping the equation balanced:

#T + color(red)(15) = 1/3R - 15 + color(red)(15)#

#T + 15 = 1/3R - 0#

#T + 15 = 1/3R#

Step 2) Multiply each side by #color(red)(3)# to solve for #R# while keeping the equation balanced:

#color(red)(3)(T + 15) = color(red)(3) xx 1/3R#

#color(red)(3)T + (color(red)(3) xx 15) = color(red)(3)/3R#

#3T + 45 = 1R#

#3T + 45 = R#

#R = 3T + 45#

Answer 2 · 2017-09-03T18:34:24

#R = 3(T+15)#

Or

#R =3T+45#

You need to make #R# the subject of the formula.

#color(blue)(1/3R)-15 = T" "larr# isolate the term which contains #R#

Add #15# to both sides to get:

#1/3color(red)(R)= T+15" "larr# isolate #R# by multiplying by #3#

#R = 3(T+15)#

This can also be simplified to

#R =3T+45#