One integer is 15 more than 3/4 of another integer. The sum of the integers is greater than 49. How do you find the least values for these two integers?

Question

3264 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-11T11:51:59

The 2 integers are 20 and 30.

Let x be an integer
Then #3/4x+15# is the second integer

Since the sum of the integers is greater than 49,
#x+3/4x+15 >49#

#x+3/4x >49-15#

#7/4x > 34#

#x > 34times4/7#

#x > 19 3/7#

Therefore, the smallest integer is #20# and the second integer is #20times3/4+15 = 15+15= 30#.