Mrs. Phillips has 10 identical cans without labels. She knows that she had 1 can of peas, 5 cans of corn, 1 can of carrots, and 3 cans of beets. She opens one can. What is the probability it is carrots?Corn or beets?

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Mrs. Phillips has 10 identical cans without labels. She knows that she had 1 can of peas, 5 cans of corn, 1 can of carrots, and 3 cans of beets. She opens one can. What is the probability it is carrots?Corn or beets?

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Answer 1 · 2017-02-27T08:18:02

$P("carrots") = 1/10$

$P("corn or beets") = 8/10 = 4/5$

Explanation:

The formula to determine the probability of an event occurring is:

$"the number of desirable outcomes"/"total number of possible outcomes"$

Only 1 of the 10 identical cans are carrots.

$P("carrots") = 1/10$

There are 8 cans which have corn or beets.

$P("corn or beets") = 8/10 = 4/5$

Notice that, when options are available, "OR" increases the probability. In this case, if the lady is equally happy to open a can of beet or corn, there are 8 tins which will meet this requriement.

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Mrs. Phillips has 10 identical cans without labels. She knows that she had 1 can of peas, 5 cans of corn, 1 can of carrots, and 3 cans of beets. She opens one can. What is the probability it is carrots?Corn or beets?

1 Answer

Explanation:

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