Marryam has a bottle of 5% acetic acid and a bottle of of 10% acetic acid. How much of each should she use to make 250 mL of 8 acetic acid?

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Answer 1 · 2018-05-23T08:08:21

Please see the explanation below

Apply a material balance with respect to acetic acid.

Volume of $8 %$ $8%$ acetic acid is $V = 250 m l$ $V=250ml$

Volume of $5 %$ $5%$ acetic acid is $= x m l$ $=xml$

Volume of $10 %$ $10%$ acetic acid is $= (250 - x) m l$ $=(250-x)ml$

Therefore,

$\frac{8}{100} \cdot 250 = \frac{5}{100} \cdot x + \frac{10}{100} \cdot (250 - x)$ $8/100*250=5/100*x+10/100*(250-x)$

Solving this equation for $x$ $x$

$0.05 x + 25 - 0.1 x = 20$ $0.05x+25-0.1x=20$

$0.05 x = 5$ $0.05x=5$

$x = 100$ $x=100$

So,

Volume of $5 %$ $5%$ acetic acid is $= 100 m l$ $=100ml$

Volume of $10 %$ $10%$ acetic acid is $= 150 m l$ $=150ml$