Log 2 (x+5)-log 2 (2x-1)=5? Precalculus Properties of Logarithmic Functions Logarithm-- Inverse of an Exponential Function 1 Answer grace ยท Stefan V. May 21, 2018 x=37/63 Explanation: log_2 ((x+5)/(2x-1))=5" " (condense it) 2^5 =(x+5)/(2x-1)" " (2=base, and it stays, log becomes exponent) 32/1=(x+5)/(2x-1)" " (cross multiply -> 32 xx (2x-1)) 64x-32=x+5 " " (simplify) 63x=37 x=37/63 Answer link Related questions What is a logarithm? What are common mistakes students make with logarithms? How can a logarithmic equation be solved by graphing? How can I calculate a logarithm without a calculator? How can logarithms be used to solve exponential equations? How do logarithmic functions work? What is the logarithm of a negative number? What is the logarithm of zero? How do I find the logarithm log_(1/4) 1/64? How do I find the logarithm log_(2/3)(8/27)? See all questions in Logarithm-- Inverse of an Exponential Function Impact of this question 6661 views around the world You can reuse this answer Creative Commons License
