Limit as x approaches infinity $(3x-2)/(2x+1)$ ?

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Answer 1 · 2014-12-23T00:21:05

$lim_(x->oo)(3x-2)/(2x+1)=3/2$

You can think that when $x$ becomes VERY big (say $1,000,000$ ) you are basically left with $(3,000,000-2)/(2,000,000+1)~=3/2$

to check your result you can evaluate it as:

$lim_(x->oo)(3x-2)/(2x+1)=lim_(x->oo)(x(3-2/x))/(x(2+1/x))=3/2$

Where:

simplify $x$

and remember that when $x->oo$ :

$2/x->0$
$1/x->0$

Limit as x approaches infinity (3x-2)/(2x+1)(3x-2)/(2x+1)?