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Let #x = e^t + 3# and #y = e^(2t)+6e^t+9# how do you eliminate the parameter and write y in terms of x?

1 Answer

Sep 17, 2016

#y=x^2#.

Explanation:

Observe that, #y=e^(2t)+6e^t+9=(e^t+3)^2=x^2#

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