Jacques can buy six CDs and three video cassettes for $163.7 or he can buy nine CDs and two video cassettes for $200.53. How do you find the price of one video cassette?

Question

Jacques can buy six CDs and three video cassettes for $163.7 or he can buy nine CDs and two video cassettes for $200.53. How do you find the price of one video cassette?

1 Answer

Impact of this question

3555 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-29T20:40:09

I got: $$ 18.01$ $$18.01$ for the VHS and $$ 18.28$ $$18.28$ for the CDs.

Explanation:

Let us call the price of CDs $c$ $c$ and of the Videos $v$ $v$ ; we can write:
$6 c + 3 v = 163.7$ $6c+3v=163.7$
$9 c + 2 v = 200.53$ $9c+2v=200.53$

we can isolate $c$ $c$ from the first and substitute into the second:
$c = \frac{163.7 - 3 v}{6}$ $c=(163.7-3v)/6$
and:
$9 \frac{163.7 - 3 v}{6} + 2 v = 200.53$ $9(163.7-3v)/6+2v=200.53$
$1473.3 - 27 v + 12 v = 1203.18$ $1473.3-27v+12v=1203.18$

$v = 18.01$ $v=18.01$

and so:

$c = \frac{163.7 - 3 \cdot 18.01}{6} = 18.28$ $c=(163.7-3*18.01)/6=18.28$

Considering that nowadays it is almost impossible to find video cassettes and even CDs are difficult to come by....I suspect the exercise is quite old!

Science

Math

Humanities

... and beyond

Jacques can buy six CDs and three video cassettes for $163.7 or he can buy nine CDs and two video cassettes for $200.53. How do you find the price of one video cassette?

1 Answer

Explanation:

Related questions

Impact of this question