Jacques can buy six CDs and three video cassettes for $163.7 or he can buy nine CDs and two video cassettes for $200.53. How do you find the price of one video cassette?

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Jacques can buy six CDs and three video cassettes for $163.7 or he can buy nine CDs and two video cassettes for $200.53. How do you find the price of one video cassette?

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Answer 1 · 2016-11-29T20:40:09

I got: $$ 18.01$ $$18.01$ for the VHS and $$ 18.28$ $$18.28$ for the CDs.

Explanation:

Let us call the price of CDs $c$ $c$ and of the Videos $v$ $v$ ; we can write:
$6 c + 3 v = 163.7$ $6c+3v=163.7$
$9 c + 2 v = 200.53$ $9c+2v=200.53$

we can isolate $c$ $c$ from the first and substitute into the second:
$c = \frac{163.7 - 3 v}{6}$ $c=(163.7-3v)/6$
and:
$9 \frac{163.7 - 3 v}{6} + 2 v = 200.53$ $9(163.7-3v)/6+2v=200.53$
$1473.3 - 27 v + 12 v = 1203.18$ $1473.3-27v+12v=1203.18$

$v = 18.01$ $v=18.01$

and so:

$c = \frac{163.7 - 3 \cdot 18.01}{6} = 18.28$ $c=(163.7-3*18.01)/6=18.28$

Considering that nowadays it is almost impossible to find video cassettes and even CDs are difficult to come by....I suspect the exercise is quite old!

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Jacques can buy six CDs and three video cassettes for $163.7 or he can buy nine CDs and two video cassettes for $200.53. How do you find the price of one video cassette?

1 Answer

Explanation:

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