Is this equation $2Al + 3NiB _ { 2} -> AlB r _ { 3} + 3N _ { i }$ balanced?

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Answer 1 · 2017-09-13T06:44:41

No.

No.

A balanced equation displays an equal amount of atoms of each element on both sides of the yield arrow.

From what you gave us/me, there are:

$2$ $Al$ atoms on the reactant's side, but only $1$ on the product's.
an equal amount of $Ni$ atoms, with $3$ atoms on each side... unless the product's $Ni$ is not a typo and is supposed to be $N_"i"$ .
$2$ $Br$ atoms on the reactant's side and $3$ on the product's... unless it's supposed to be $B$ (boron).

In order to balance this equation, we have to play around with the coefficients so that each atom on the reactant's is equal to the to product's.

You should get this:

$2Al + 3NiBr_"2" -> 2AlBr_"3" + 3Ni$

Now if we look at this equation, there are an equal amount of every atom on both sides of the yield arrow.

Hope this helps :)

Is this equation 2Al + 3NiB _ { 2} -> AlB r _ { 3} + 3N _ { i }2Al + 3NiB _ { 2} -> AlB r _ { 3} + 3N _ { i } balanced?