Is the following equation balanced? NH2CH2COOH (s) + 9/4 O2 --> 2 CO2 (s) + 5/2 H2O (l) + 1/2 N2 (g)

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Is the following equation balanced? NH2CH2COOH (s) + 9/4 O2 --> 2 CO2 (s) + 5/2 H2O (l) + 1/2 N2 (g)

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Answer 1 · 2015-11-10T06:51:42

The correct equation is ${4NH}_{2} {CH}_{2} COOH(s) + {9O}_{2} (g)$ $"4NH"_2"CH"_2"COOH(s)" + "9O"_2("g")"$ $\to$ $rarr$ ${8CO}_{2} (g) + 10 H_{2} O (l) {+ 2N}_{2}$ $"8CO"_2("g") + 10"H"_2"O"("l")" + 2N"_2"$ .

Explanation:

It is not properly balanced. A balanced equation should have only whole number coefficients.

${NH}_{2} {CH}_{2} COOH(s) + {9/4O}_{2} (g)$ $"NH"_2"CH"_2"COOH(s)" + "9/4O"_2("g")"$ $\to$ $rarr$ ${2CO}_{2} (g) + {5/2H}_{2} O (l) + {1/2N}_{2} (g)$ $"2CO"_2("g") + "5/2H"_2"O"("l") + "1/2N"_2("g")"$

The common denominator of the fraction coefficients is 4. Multiply all coefficients times 4.

${4NH}_{2} {CH}_{2} COOH(s) + {9O}_{2} (g)$ $"4NH"_2"CH"_2"COOH(s)" + "9O"_2("g")"$ $\to$ $rarr$ ${8CO}_{2} (g) + \frac{5 \cdot 4}{2} H_{2} O (l) + \frac{1 \cdot 4}{2} N_{2}$ $"8CO"_2("g") + (5*4)/2"H"_2"O"("l")" + (1*4)/2N_2$

Simplify the fractions on the right side of the equation.

${4NH}_{2} {CH}_{2} COOH(s) + {9O}_{2} (g)$ $"4NH"_2"CH"_2"COOH(s)" + "9O"_2("g")"$ $\to$ $rarr$ ${8CO}_{2} (g) + \frac{20}{2} H_{2} O (l) + \frac{4}{2} N_{2}$ $"8CO"_2("g") + 20/2"H"_2"O"("l")" + 4/2N_2$

Reduce the fractions on the right side.

${4NH}_{2} {CH}_{2} COOH(s) + {9O}_{2} (g)$ $"4NH"_2"CH"_2"COOH(s)" + "9O"_2("g")"$ $\to$ $rarr$ ${8CO}_{2} (g) + 10 H_{2} O (l) {+ 2N}_{2}$ $"8CO"_2("g") + 10"H"_2"O"("l")" + 2N"_2"$

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Is the following equation balanced? NH2CH2COOH (s) + 9/4 O2 --> 2 CO2 (s) + 5/2 H2O (l) + 1/2 N2 (g)

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