In simplest radical form, what is #sqrt845# equal to? Algebra Radicals and Geometry Connections Simplification of Radical Expressions 1 Answer Don't Memorise Apr 11, 2015 The number #845# is divisible by 5. It equals #5*169# #color(red)(sqrt845# #= sqrt(5*169)# #= sqrt(5)*sqrt(169)# (In general, #color(blue)(sqrt(a*b) = sqrt(a)*sqrt(b)#) #= sqrt(5)*13# (Because #sqrt169 = 13#) #= color(green)(13*sqrt(5)# #sqrt845# in the Simplest Radical form is #color(green)(13*sqrt(5)# Answer link Related questions How do you simplify radical expressions? How do you simplify radical expressions with fractions? How do you simplify radical expressions with variables? What are radical expressions? How do you simplify #root{3}{-125}#? How do you write # ""^4sqrt(zw)# as a rational exponent? How do you simplify # ""^5sqrt(96)# How do you write # ""^9sqrt(y^3)# as a rational exponent? How do you simplify #sqrt(75a^12b^3c^5)#? How do you simplify #sqrt(50)-sqrt(2)#? See all questions in Simplification of Radical Expressions Impact of this question 3633 views around the world You can reuse this answer Creative Commons License