If Y varies inversely as twice x and when x = 3, y = 8 how do you find y when x = 2?

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Answer 1 · 2017-05-29T13:42:58

When #x=2, y = 12#

#y = k/(2x)," "# which can be written as #" "k = 2x xx y#

#y = k/(2x) = 48/(2xx2)#

# = 48/4 = 12#

Answer 2 · 2017-05-29T13:50:14

y = 12

Here #y prop 1/(2x)#

or, #y = k. 1/(2x)# ..............(i)

put x = 3 & y = 8 we get, #8 = k. 1/(2xx3)#

#rArr k = 48#

Again putting the value of k & x in (i) to find 'y'

#rArr y = 48. 1/(2xx2)#

#rArr y = 12#