If Y varies inversely as twice x and when x = 3, y = 8 how do you find y when x = 2?

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Answer 1 · 2017-05-29T13:42:58

When $x=2, y = 12$

$y = k/(2x)," "$ which can be written as $" "k = 2x xx y$

$y = k/(2x) = 48/(2xx2)$

$= 48/4 = 12$

Answer 2 · 2017-05-29T13:50:14

y = 12

Here $y prop 1/(2x)$

or, $y = k. 1/(2x)$ ..............(i)

put x = 3 & y = 8 we get, $8 = k. 1/(2xx3)$

$rArr k = 48$

Again putting the value of k & x in (i) to find 'y'

$rArr y = 48. 1/(2xx2)$

$rArr y = 12$