If y varies inversely as the cube root of x, and y = 12 when x = 8, how do you find y when x = 1?

Question

21787 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-07-03T09:18:58

#24#

Write the english as maths: #y prop1/root(3)x#

Change the variation to an equation by multiplying by a constant.

#y = k/root(3)x" we need to find a value for "k#

#k = root(3)x xx y = root(3)8 xx 12 = 2 xx 12 = 24#

Replace #k# with #24# to obtain the equation

#y = 24/root(3)x#

Now we can calculate y for any given x.

#y = 24/root(3)1 =24/1 =24#