If $x^{2} = 4 (5 - 1)$ $x^2=4(5-1)$ what is the value of x?

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Answer 1 · 2016-11-28T19:39:49

This equation has 2 solutions: $x = - 4 \lor x = 4$ $x=-4 vv x=4$

$x^{2} = 4 (5 - 1)$ $x^2=4(5-1)$ First we have to multiply the right side.

$x^{2} = 4 \cdot 4$ $x^2=4*4$

$x^{2} = 16$ $x^2=16$ Now we can take a square root of both sides remembering that $\sqrt{x^{2}} = | x |$ $sqrt(x^2)=|x|$

$| x | = 4$ $|x|=4$

$x = - 4 \lor x = 4$ $x=-4 vv x=4$

If x^2=4(5-1)x2=4(5−1)x^2=4(5-1) what is the value of x?