If $x^2=4(5-1)$ what is the value of x?

Question

4271 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-28T19:39:49

This equation has 2 solutions: $x=-4 vv x=4$

$x^2=4(5-1)$ First we have to multiply the right side.

$x^2=4*4$

$x^2=16$ Now we can take a square root of both sides remembering that $sqrt(x^2)=|x|$

$|x|=4$

$x=-4 vv x=4$

If x^2=4(5-1)x^2=4(5-1) what is the value of x?