If w is a complex cube roots of unity then w^17: 1. 0 2. 1 3. w 4. w^2 Pleas explain? Precalculus Complex Zeros Complex Conjugate Zeros 1 Answer Ratnaker Mehta Apr 16, 2017 #omega in CC# is a cube-root of unity #:. omega^3=1.# #:. omega^17=omega^(15+2)=omega^15*omega^2=((omega^3)^5)*omega^2=((1)^5)*omega^2=omega^2.# #:." Answer : Option 4. "omega^2.# Answer link Related questions What is a complex conjugate? How do I find a complex conjugate? What is the conjugate zeros theorem? How do I use the conjugate zeros theorem? What is the conjugate pair theorem? How do I find the complex conjugate of #10+6i#? How do I find the complex conjugate of #14+12i#? What is the complex conjugate for the number #7-3i#? What is the complex conjugate of #3i+4#? What is the complex conjugate of #a-bi#? See all questions in Complex Conjugate Zeros Impact of this question 1922 views around the world You can reuse this answer Creative Commons License