How do I find the complex conjugate of 10+6i?

1 Answer
Jim G.
Mar 23, 2018

10-6i

Explanation:

"Given a complex number "z=a+-bi" then"

"the "color(blue)"complex conjugate "=acolor(red)(∓)bi

"note that the product of a complex number and it's"
"conjugate results in a real number"

(a+bi)(acolor(red)(-)bi)=a^2+b^2larrcolor(blue)"real number"

"the conjugate of "10+6i" is "10color(red)(-)6i

"and "(10+6i)(10-6i)=100+36=136larrcolor(red)"real"

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