If the range of the function $y = a \sqrt{x}$ $y=asqrtx$ is ${y ∣ y \leq 0}$ ${y|y<=0}$ , what can you conclude about the value of a?

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If the range of the function $y = a \sqrt{x}$ $y=asqrtx$ is ${y ∣ y \leq 0}$ ${y|y<=0}$ , what can you conclude about the value of a?

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Answer 1 · 2017-03-19T21:48:46

$a$ $a$ is a negative constant.

Explanation:

The function $y = \sqrt{x}$ $y=sqrtx$ has the range $y \geq 0$ $y>=0$ . So if $y = a \sqrt{x}$ $y=asqrtx$ has the range $y \leq 0$ $y<=0$ , then we know $a < 0$ $a < 0$ .

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If the range of the function $y = a \sqrt{x}$ $y=asqrtx$ is ${y ∣ y \leq 0}$ ${y|y<=0}$ , what can you conclude about the value of a?

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Explanation:

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If the range of the function $y = a \sqrt{x}$ $y=asqrtx$ is ${y ∣ y \leq 0}$ ${y|y<=0}$ , what can you conclude about the value of a?