If the perimeter of a rectangle is 5x2+2xy7y2+16, and the length is 2x2+6xyy2+15, what is the width?

1 Answer
Oct 27, 2016

W=92x25xy52y27

Explanation:

Name P the perimeter of the rectangle.
Name L its length and W its width.

Given:
P=5x2+2xy7y2+16

L=2x2+6xyy2+15

PRec=2(L+W)

5x2+2xy7y2+16=2(2x2+6xyy2+15+W)

5x2+2xy7y2+16=4x2+12xy2y2+30+2W

5x2+2xy7y2+16+4x212xy+2y230=+2W

5x2+4x2+2xy12xy7y2+2y2+1630=+2W

9x210xy5y214=+2W

9x210xy5y2142=W

92x25xy52y27=W