If $sqrt(x-1)=2$ , what is $(x - 1)^2$ ?

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If $sqrt(x-1)=2$ , what is $(x - 1)^2$ ?

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Answer 1 · 2018-04-22T18:24:04

$(x-1)^2=16$

Explanation:

Square both sides:

$(sqrt(x-1))^2=(2)^2$

This causes the radical to cancel out:

$(x-1)=4$

Square both sides, again:

$(x-1)^2=4^2$

$(x-1)^2=16$

Answer 2 · 2018-04-22T18:30:02

$(x-1)^2=16$

Explanation:

$color(blue)"square both sides"$

$"note that "sqrtaxxsqrta=(sqrta)^2=a$

$rArr(sqrt(x-1))^2=2^2$

$rArrx-1=4$

$color(blue)"square both sides"$

$(x-1)^2=4^2$

$rArr(x-1)^2=16$

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If $sqrt(x-1)=2$ , what is $(x - 1)^2$ ?

2 Answers

Explanation:

Explanation:

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If $sqrt(x-1)=2$ , what is $(x - 1)^2$ ?