If #cosA=3/10# what is #tanA#?

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If #cosA=3/10# what is #tanA#?

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Answer 1 · 2016-12-14T00:47:28

#tanA=sqrt(91)/3#

Explanation:

Since the cosine ratio is the adjacent over the hypotenuse, we can use the Pythagorean Theorem to solve for the third side (opposite leg). #3^2+y^2=10^2#
So, #y^2=100-9# or #y^2=91#
then, #y=sqrt(91)#.

Tangent of angle A will be: #sqrt(91)/3#

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If #cosA=3/10# what is #tanA#?

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