If 25.21 mL of NaOH solution is required to react completely with .550 g KHP, what is the molarity of the NaOH solution?

1 Answer
anor277
May 14, 2016

Rxn: C_6H_4(CO_2H)(CO_2^(-)K^(+)) + NaOH(aq) rarr C_6H_4(CO_2^(-)Na^+)(CO_2^(-)K^(+)) + H_2O

Explanation:

Given the equation, there is 1:1 equivalence between moles of KHP and moles of sodium hydroxide.

"Moles of KHP" = (0.550*g)/(204.22*g*mol^-1) = 2.69xx10^-3*mol

"Concentration of NaOH(aq) solution:" = (2.69xx10^-3*mol)/(25.21xx10^-3*L) ~= 0.100*mol*L^-1, but do the calculation for an exact value.

"KHP" is an excellen primary standard, because we could also have used it as a base and not an acid, and used it to standardize a hydrochloirc acid solution.

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