If 0.31 mol of $N a_{2} S O_{4}$ $Na_2SO_4$ dissolve in water to make 740 mL of solution, how would you find the molarity of the resulting solution?

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Answer 1 · 2017-03-04T20:57:24

$Molarity = \frac{Moles of solute}{Volume of solution}$ $"Molarity"="Moles of solute"/"Volume of solution"$

And thus for the molarity of the given solution, we have:

$(0.31*mol)/(740*cancel(mL)xx10^-3*L*cancel(mL^-1))=0.42*mol*L^-1$

with respect to $Na_2SO_4$ . What is the molarity with respect to sodium ion?

If 0.31 mol of Na_2SO_4Na2SO4Na_2SO_4 dissolve in water to make 740 mL of solution, how would you find the molarity of the resulting solution?