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If 0.31 mol of #Na_2SO_4# dissolve in water to make 740 mL of solution, how would you find the molarity of the resulting solution?

1 Answer

Mar 4, 2017

#"Molarity"="Moles of solute"/"Volume of solution"#

Explanation:

And thus for the molarity of the given solution, we have:

#(0.31*mol)/(740*cancel(mL)xx10^-3*L*cancel(mL^-1))=0.42*mol*L^-1#

with respect to #Na_2SO_4#. What is the molarity with respect to sodium ion?

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