I have 5 blue socks, 3 red socks, 4 green socks. I take two socks from the drawer. How do you list all the possible outcomes for the two socks?

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I have 5 blue socks, 3 red socks, 4 green socks. I take two socks from the drawer. How do you list all the possible outcomes for the two socks?

1 Answer

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Answer 1 · 2017-06-20T12:18:26

$B, B = \frac{20}{132}, R, R = \frac{6}{132}, G, G = \frac{12}{132}, B & G = \frac{40}{132}, B & R = \frac{30}{132}, R & G = \frac{24}{132}$ $B,B=20/132,R,R= 6/132 , G,G=12/132, B &G = 40/132 , B & R =30/132, R & G = 24/132$

Explanation:

Blue: $B$ $B$ , Red: $R$ $R$ , Green: $G$ $G$
$B = 5, R = 3, G = 4; T = (5 + 3 + 4) = 12$ $B=5, R=3, G=4 ; T=(5+3+4)=12$

Probability:Blue -first
$B, B = \frac{5}{12} \cdot \frac{4}{11} = \frac{20}{132}$ $B,B = 5/12*4/11=20/132$
$B, R = \frac{5}{12} \cdot \frac{3}{11} = \frac{15}{132}$ $B,R = 5/12*3/11=15/132$
$B, G = \frac{5}{12} \cdot \frac{4}{11} = \frac{20}{132}$ $B,G = 5/12*4/11=20/132$
Red -first
$R, R = \frac{3}{12} \cdot \frac{2}{11} = \frac{6}{132}$ $R,R = 3/12*2/11=6/132$
$R, B = \frac{3}{12} \cdot \frac{5}{11} = \frac{15}{132}$ $R,B = 3/12*5/11=15/132$
$R, G = \frac{3}{12} \cdot \frac{4}{11} = \frac{12}{132}$ $R,G = 3/12*4/11=12/132$
Green -first
$G, G = \frac{4}{12} \cdot \frac{3}{11} = \frac{12}{132}$ $G,G = 4/12*3/11=12/132$
$G, B = \frac{4}{12} \cdot \frac{5}{11} = \frac{20}{132}$ $G,B = 4/12*5/11=20/132$
$G, R = \frac{4}{12} \cdot \frac{3}{11} = \frac{12}{132}$ $G,R = 4/12*3/11=12/132$

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I have 5 blue socks, 3 red socks, 4 green socks. I take two socks from the drawer. How do you list all the possible outcomes for the two socks?

1 Answer

Explanation:

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