How would you prepare 250. mL of a 0.175 M solution of Cobalt(II) Chloride from the solid and distilled water?

1 Answer
Mar 15, 2018

Consider that solutions are solutes dissolved in solvent.

Here, our solute is cobalt (II) chloride and our solvent is distilled water.

The volume of solute is generally ignored, so we would dissolve,

250"mL" * "L"/(10^3"mL") * 0.175"M" * (129.9"g")/"mol" approx 5.68"g"250mLL103mL0.175M129.9gmol5.68g

of cobalt (II) chloride in approximately 250"mL"250mL of distilled water to create the solution in the lab.