How would you balance "H"_3"BO"_3"rarr"H"_4"B"_6"O"_11" +H"_2"O"?

1 Answer
Jul 31, 2018

color(darkgreen)(6) color(white)(l)"H"_3color(black)("B")"O"_3 rarr color(darkgreen)(1) color(white)(l) "H"_4color(black)("B"_6) "O"_11 + color(darkgreen)(7) color(white)(l) "H"_2"O"

Explanation:

This answer balances the equation by equating (the conservation of) the number of boron atoms on both sides of the equation.

"H"_3"BO"_3 and "H"_4"B"_6"O"_11 are the only two boron-containing species in this reaction. Each molecule of "H"_3 color(navy)("B")"O"_3 contains one boron "B" atom whereas each molecule of "H"_4color(navy)("B"_6)"O"_11 contains six. Add the coefficient "color(navy)(6) to the front of "H"_3 "BO"_3 and color(navy)(1) to "H"_4"B"_6"O"_11 balance the number of boron atoms on the two sides.

color(purple)(6) color(white)(l)"H"_3color(navy)("B")"O"_3 rarr color(purple)(1) color(white)(l) "H"_4color(navy)("B"_6) "O"_11 + "H"_2"O" color(grey)("NOT BALANCED")

The left-hand side of the equation contains 6 xx 3 =18 oxygen "O" atoms. The number of oxygen atoms shall also conserve in this equation. Therefore "H"_4"B"_6"O"_11 and "H"_2"O" on the product side shall contain a total of 18 oxygen atoms. 11 of them go to the "H"_4color(navy)("B"_6)"O"_11 molecule. Water molecules would account for rest 7 oxygen atoms.

Each water molecule contains one single oxygen atom. 7 of the oxygen atoms would thus correspond to 7 water molecules on the product side. Hence the equation:

color(black)(6) color(white)(l)"H"_3color(black)("B")"O"_3 rarr color(black)(1) color(white)(l) "H"_4color(black)("B"_6) "O"_11 + color(purple)(7) color(white)(l) "H"_2"O"

Optionally, check if the number of hydrogen "H" atoms on the two sides conserves to see if the equation is properly balanced:

  • Number of "H" atoms on the right-hand side: 6 xx 3 = 18
  • Number of "H" atoms on the left-hand side: 1 xx 4 + 7 xx 2 = 18

The two numbers are equal, and thus this chemical equation is stoichiometrically balanced.

color(darkgreen)(6) color(white)(l)"H"_3color(black)("B")"O"_3 rarr color(darkgreen)(1) color(white)(l) "H"_4color(black)("B"_6) "O"_11 + color(darkgreen)(7) color(white)(l) "H"_2"O" color(grey)("Balanced")

Reference
"Balance Chemical Equation - Online Balancer," webqc.org,
https://www.webqc.org/balance.php, "Enter H3BO3 = H4B6O11 + H2O for this equation."