How to you find the general solution of #dy/dx=xe^(x^2)#?
1 Answer
Nov 23, 2016
# y = 1/2e^(x^2) + c #
Explanation:
This is a First Order Separable DE, so we can just separate the variable in it's current form to give;
# int dy = int xe^(x^2) dx #
And note we can re-write as:
# int dy = 1/2int 2xe^(x^2) dx #
So we can integrate to give:
# y = 1/2e^(x^2) + c #
