How to use the discriminant to find out what type of solutions the equation has for 5n² + 6n + 7 = n² - 4n?

1 Answer
Jun 6, 2015

First subtract n^2-4n from both sides to get:

4n^2+10n+7 = 0

This is of the form an^2+bn+c = 0, with a=4, b=10 and c=7

The discriminant is given by the formula:

Delta = b^2-4ac = 10^2-(4xx4xx7) = 100-112 = -12

Since Delta < 0 the quadratic has no real solutions. It has two distinct complex roots.

In general, the possible cases are:

Delta = 0 : Means the quadratic has one repeated real root. If the coefficients of the quadratic are rational, that repeated root is also rational.

Delta > 0 : Means that the quadratic has two distinct real roots. If Delta is also a perfect square and the coefficients of the quadratic are rational, then those roots are also rational.

Delta < 0 : Means that the quadratic has no real roots. It has two distinct complex roots which are complex conjugates of one another.