How to use the discriminant to find out what type of solutions the equation has for $2 x^{2} + 9 = 4 x$ $2x^2+9=4x$ ?

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Answer 1 · 2015-05-23T22:59:54

y = 2x^2 - 4x + 9

D = b^2 - 4ac = 16 - 72 = -56. < 0.

There are no real roots. There are 2 complex roots.

How to use the discriminant to find out what type of solutions the equation has for 2x2+9=4x2x^2+9=4x?