How to use the discriminant to find out what type of solutions the equation has for $x^{2} + 3 x + 8 = 0$ $x^2+3x+8=0$ ?

Question

How to use the discriminant to find out what type of solutions the equation has for $x^{2} + 3 x + 8 = 0$ $x^2+3x+8=0$ ?

1 Answer

Impact of this question

1531 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-05-26T17:56:47

This equation has no real solutions.

The rule is that:

If $Delta<0$ then there are no real solutions (there are 2 complex solutions)
If $Delta=0$ then there is one real solution ( $x_0=-b/(2a)$ )
If $Delta>0$ then there are 2 real solutions which you can calculate using:
$x_1=(-b-sqrt(Delta))/(2a)$ and $x_2=(-b+sqrt(Delta))/(2a)$

Science

Math

Humanities

... and beyond

How to use the discriminant to find out what type of solutions the equation has for $x^{2} + 3 x + 8 = 0$ $x^2+3x+8=0$ ?

1 Answer

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How to use the discriminant to find out what type of solutions the equation has for x^2+3x+8=0x2+3x+8=0x^2+3x+8=0?

1 Answer

Related questions

Impact of this question

How to use the discriminant to find out what type of solutions the equation has for $x^{2} + 3 x + 8 = 0$ $x^2+3x+8=0$ ?