How to use the discriminant to find out what type of solutions the equation has for $x^{2} + 5 x + 6 = 0$ $x^2 + 5x + 6 = 0$ ?

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Answer 1 · 2015-05-18T00:35:55

x^2 + 5x + 6 = 0

D = d^2 = 25 - 24 = 1. d = +- 1.

There are 2 real roots: $x = - \frac{b}{2 a} \pm \frac{d}{2 a}$ $x = -b/(2a) +- d/(2a)$

$x = - \frac{5}{2} + \frac{1}{2} = - \frac{4}{2} = - 2$ $x = -5/2 + 1/2 = -4/2 = -2$

$x = - \frac{5}{2} - \frac{1}{2} = - \frac{6}{2} = - 3$ $x = -5/2 - 1/2 = -6/2 = -3$ .

There is a new method, called new AC Method that may be simpler and faster.
Find 2 number knowing sum (= -5) and product (= 6). They are -2 and -3.

How to use the discriminant to find out what type of solutions the equation has for x^2 + 5x + 6 = 0x2+5x+6=0x^2 + 5x + 6 = 0?