How to use the discriminant to find out what type of solutions the equation has for $x^{2} + 2 x + 5 = 0$ $x^2 + 2x + 5 = 0$ ?

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Answer 1 · 2015-06-07T11:38:36

$x^{2} + 2 x + 5 = 0$ $x^2 + 2x + 5 = 0$

The Discriminant is given by:
$Delta=b^2-4*a*c$

$= (2)^2-(4*1*5)$

$= 4-20=-16$

As $Delta = -16$ , this equation has NO REAL SOLUTIONS
- Note :
The solutions are normally found using the formula
$x=(-b+-sqrtDelta)/(2*a)$

As $Delta = -16$ , $x = ((-2)+-sqrt(-16))/(2*1) = (-2+-sqrt(-16))/2$

How to use the discriminant to find out what type of solutions the equation has for x^2 + 2x + 5 = 0x2+2x+5=0x^2 + 2x + 5 = 0?