How to use the discriminant to find out how many real number roots an equation has for $5 x^{2} + 11 x + 8 = 0$ $5x^2 + 11x + 8 = 0$ ?

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Answer 1 · 2015-05-18T03:43:21

$D = d^{2} = b^{2} - 4 a c = 121 - 160 = - 39 < 0$ $D = d^2 = b^2 - 4ac = 121 - 160 = -39 < 0$

There are no real roots.

How to use the discriminant to find out how many real number roots an equation has for 5x2+11x+8=05x^2 + 11x + 8 = 0?