How to use the discriminant to find out how many real number roots an equation has for $x^{2} + 4 x + 10 = 0$ $x^2 + 4x + 10 = 0$ ?

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Answer 1 · 2015-05-26T23:58:52

x^2 + 4x + 10 = 0

D = 16 - 40 = -24 < 0.

There are 2 complex roots.

How to use the discriminant to find out how many real number roots an equation has for x^2 + 4x + 10 = 0x2+4x+10=0x^2 + 4x + 10 = 0?