How to use the discriminant to find out how many real number roots an equation has for $x^{2} - 4 x + 3 = 0$ $x^2 - 4x + 3 = 0$ ?

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How to use the discriminant to find out how many real number roots an equation has for $x^{2} - 4 x + 3 = 0$ $x^2 - 4x + 3 = 0$ ?

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Answer 1 · 2018-04-16T01:33:18

$TWO REAL ROOTS$ $color(purple)("TWO REAL ROOTS"$

Explanation:

$x^{2} - 4 x + 3$ $x^2 - 4x + 3$

$Discriminant D = b^{2} - 4 a c$ $"Discriminant " D = b^2 - 4ac$

![http://slideplayer.com/slide/7936589/]( useruploads.socratic.org )

In this case,

$D = b^{2} - 4 a c = 16 - (4 \cdot 1 \cdot 3) = 4, which is > 0 and hence has two real roots, \pm 2$ $color(brown)(D = b^2 - 4ac) = 16 - (4 * 1 * 3) = 4, " which is "color(blue)( > 0) " and hence has two real roots ", color(green)(+-2$

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How to use the discriminant to find out how many real number roots an equation has for $x^{2} - 4 x + 3 = 0$ $x^2 - 4x + 3 = 0$ ?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How to use the discriminant to find out how many real number roots an equation has for x2−4x+3=0x^2 - 4x + 3 = 0?

1 Answer

Explanation:

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Impact of this question

How to use the discriminant to find out how many real number roots an equation has for $x^{2} - 4 x + 3 = 0$ $x^2 - 4x + 3 = 0$ ?