How to use the discriminant to find out how many real number roots an equation has for a2+12a+36=0?
2 Answers
May 20, 2018
The discriminant is:
Substitute these values into the discriminant and you should get two answers (real roots):
If the discriminant is 0 there is 1 real root, if it is > 0 there are 2 and otherwise 0 real roots.
May 20, 2018
one at
Explanation:
discriminant is the part under the square root:
if discriminant < 0 there are 2 imaginary roots
if discriminant > 0 there are 2 real roots
if discriminant = 0 there is 1 real root
if discriminant is a perfect square roots are rational
for yours:
a = 1
b = 12
c = 36
since the discriminant is 0 the function has 1 real root at
graph{x^2+12x+36 [-13.79, 6.21, -0.92, 9.08]}
