How to use the discriminant to find out how many real number roots an equation has for $x^2=4$ ?

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How to use the discriminant to find out how many real number roots an equation has for $x^2=4$ ?

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Answer 1 · 2015-05-27T17:42:25

Write your equatiom as:
$x^2-4=0$ which is in the form $ax^2+bx+c=0$
Where
$a=1$
$b=0$
$c=-4$
The discriminant $Delta$ is:
$Delta=b^2-4ac==-4(1*-4)=16>0$
The fact that $Delta>0$ tells you that your equation has 2 Real distinct solutions.

[ $x_1=2$ and $x_2=-2$ ]

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How to use the discriminant to find out how many real number roots an equation has for $x^2=4$ ?

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