How to use the discriminant to find out how many real number roots an equation has for $2x^2 + 5x - 3 = 0$ ?

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Answer 1 · 2015-05-18T00:51:27

#2x^2 + 5x - 3 = 0

D = d^2 = b^2 - 4ac = 25 + 24 = 49 -> d = +- 7

There are 2 real roots:

$x = -b/(2a) +- d/(2a) = -5/4 +- 7/4$

How to use the discriminant to find out how many real number roots an equation has for 2x^2 + 5x - 3 = 0 2x^2 + 5x - 3 = 0 ?