How to solve the system of equations #2x-y=-1# and #3x+2y=-5# by graphing?

1 Answer
Bhavin B.
Jul 24, 2018

From the graphs, we get point of intersection at #x=-1# and #y=-1#.enter image source here

Explanation:

The intercept of two linear graphs is the solution for #x# and #y#.

Lets take the first equation:
#2x-y=-1#

Find the #x# intercept and #y# intercept and plot the graph.

#x#-intercept, #y=0#
#2x-y=-1#

#2x-0=-1#

#2x=-1#

#x=-1/2# ------> #x#-Intercept

#y#-intercept, #x=0#

#2x-y=-1#

#2(0)-y=-1#

#-y=-1#

#y=1#------>#y#-Intercept

Lets take the second equation:
#3x+2y=-5#

Find the #x# intercept and #y# intercept and plot the graph.

#x#-intercept, #y=0#
#3x+2y=-5#

#3x+2(0)=-5#

#3x=-5#

#x=-5/3# -----> #x#-Intercept

#y#-intercept, #x=0#
#3x+2y=-5#

#3(0)+2y=-5#

#2y=-5#

#y=-5/2#------> #y#-Intercept

**Now plot the two linear graphs and from the graph, the intersection of these tow linear graphs are the value of #x# and #y# satisfying both the equations. Graphs are shown below:

From the graphs, we get point of intersection at #x=-1# and #y=-1#.

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