How to find the y-intercept given $y = x^{2} + 2 x - 3$ $y = x^2 + 2x - 3$ ?

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Answer 1 · 2015-05-03T03:57:16

The $y$ $y$ intercept is a point on the $y$ $y$ -axis. Where the $x$ $x$ -coefficients are all $0$ $0$ .

Put in $0$ $0$ for $x$ $x$ and find $y$ $y$ .

$y = {(0)}^{2} + 2 (0) - 3 = 3$ $y= (0)^2+2(0)-3=3$

The $y$ $y$ -intercept is $- 3$ $-3$ (or $(0, - 3)$ $(0,-3)$ depending on your grader's preference).

How to find the y-intercept given y=x2+2x−3y = x^2 + 2x - 3?