How to find the x and y-intercept given $x + 3 y = - 6$ $x+3y = -6$ ?

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Answer 1 · 2015-05-02T01:16:18

The y-intercept is $- 2$ $-2$ , and the point is $(0, - 2)$ $(0,-2)$ . The x-intercept is $- 6$ $-6$ and the point is $(- 6, 0)$ $(-6,0)$

To find the y-intercept, set x equal to zero.

$x + 3 y = - 6$ $x+3y=-6$

$0 + 3 y = - 6$ $0+3y=-6$

$3 y = - 6$ $3y=-6$

$y = - \frac{6}{3}$ $y=-6/3$

$y = - 2$ $y=-2$

To find the x-intercept, set y equal to zero.

$x + 3 y = - 6$ $x+3y=-6$

$x + 3 \cdot 0 = - 6$ $x+3*0=-6$

$x = - 6$ $x=-6$

graph{x+3y=-6 [-10, 10, -5, 5]}

How to find the x and y-intercept given x+3y = -6x+3y=−6x+3y = -6?