How to find the Range of a function f(x)= (x^3+1)^-1f(x)=(x3+1)−1?

1 Answer
Alan P.
Apr 13, 2015

f(x) = (x^3+1)^(-1)f(x)=(x3+1)−1
is equivalent to
f(x) = 1/(x^3+1)f(x)=1x3+1
which is valid for all Real values of xx except when (x^3+1) = 0(x3+1)=0

(x^3+1) = 0(x3+1)=0
implies
x=1x=1

So the Domain of f(x)f(x) is all Real numbers except 11
or in set notation
Domain of f(x) = {(-oo,1) uu (1,+oo)}f(x)={(−∞,1)∪(1,+∞)}

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