How to find instantaneous rate of change for #y(x)=1/(x+2)# at x=2?
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"How do I change #int_0^1int_0^sqrt(1-x^2)int_sqrt(x^2+y^2)^sqrt(2-x^2-y^2)xydzdydx# to cylindrical or spherical coordinates?"
1 Answer
Feb 21, 2017
Explanation:
The instantaneous rate of change of y(x) at x = 2 is y'(2)
#"Express "y(x)=1/(x+2)=(x+2)^-1# differentiate using the
#color(blue)"chain rule"#
#rArry'(x)=-(x+2)^-2 .d/dx(x+2)#
#rArry'(x)=-(x+2)^-2=-1/(x+2)^2#
#rArry'(2)=-1/(4)^2=-1/16#