How to find instantaneous rate of change for $f(x)=4 ·x^2+4 ·x−3$ when x=4?

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Answer 1 · 2016-06-02T12:57:07

36

The $color(blue)"instantaneous rate of change"$ is the value of f'(4)

$f(x)=4x^2+4x-3rArrf'(x)=8x+4$

and f'(4) = 8(4) + 4 = 32 + 4 = 36

How to find instantaneous rate of change for f(x)=4 ·x^2+4 ·x−3f(x)=4 ·x^2+4 ·x−3 when x=4?