How to do you graph $y = 4 x - 1$ $y=4x-1$ by plotting points?

Question

9044 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-04T14:28:14

See a solution process below:

To graph a linear equation you require just two points and then draw a straight line through the two points.

First, solve for two points which solve the equation and plot these points:

First Point: For $x = 0$ $x = 0$

$y = (4 \cdot 0) - 1$ $y = (4 * 0) - 1$

$y = 0 - 1$ $y = 0 - 1$

$y = - 1$ $y = -1$ or $(0, - 1)$ $(0, -1)$

Second Point: For $x = 1$ $x = 1$

$y = (4 \cdot 1) - 1$ $y = (4 * 1) - 1$

$y = 4 - 1$ $y = 4 - 1$

$y = 3$ $y = 3$ or $(1, 3)$ $(1, 3)$

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+1)^2-0.025)((x-1)^2+(y-3)^2-0.025)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y-4x+1)(x^2+(y+1)^2-0.025)((x-1)^2+(y-3)^2-0.025)=0 [-10, 10, -5, 5]}

How to do you graph y=4x−1y=4x-1 by plotting points?