How many mols of oxygen are required to react completely with 81 L of hydrogen to form water?

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Answer 1 · 2016-06-29T15:51:49

Approx. #40.5*L# of dioxygen gas.

#H_2(g) + 1/2O_2(g) rarrH_2O(l)#

Given the stoichiometry, clearly there are #"2 equiv"# dihydrogen gas per #"equiv"# dioxygen gas.

Under the same conditions of temperature and pressure, #81*L# of dihydrogen gas requires #40.5*L# dioxygen gas for stoichiometric equivalence.