How many moles of solute particles are present in 1 mL (exact) of aqueous 0.033 M pyridine $C_5H_5N$ ?

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Answer 1 · 2018-03-29T01:00:37

$3.3 × 10^-5\ "moles"$

$"Molarity" = "Moles of solute"/"Volume of solution (in litres)"$

$"n = Molarity × Volume"$

$"n = 0.033 M × 1 mL"$

$"n" = 0.033 "mol"/cancel"L" × 10^-3 cancel"L" color(white)(..)[∵ "M = mol/L & 1 mL" = 10^-3\ "L"]$

$"n" = 3.3 × 10^-5\ "mol"$

How many moles of solute particles are present in 1 mL (exact) of aqueous 0.033 M pyridine C_5H_5NC_5H_5N?